luatexja.load_module('base'); local ltjb = luatexja.base
luatexja.load_module('stack'); local ltjs = luatexja.stack
+local stack_table_index = luatexja.stack_table_index
+
+-- load jisx0208 table
+local cache_ver = 2
+
+local cache_outdate_fn = function (t) return t.version~=cache_ver end
+local jisx0208 = ltjb.load_cache('ltj-jisx0208',cache_outdate_fn)
+if not jisx0208 then -- make cache
+ jisx0208 = require('ltj-jisx0208.lua')
+ ltjb.save_cache_luc('ltj-jisx0208', jisx0208)
+end
+
-- \kuten, \jis, \euc, \sjis, \ucs, \kansuji
local function to_kansuji(num)
local s = ""
while num~=0 do
s = utf.char(
- ltjs.get_penalty_table(luatexja.stack_table_index.KSJ + num%10,
+ ltjs.get_stack_table(luatexja.stack_table_index.KSJ + num%10,
'', tex.getcount('ltj@@stack'))) .. s
num=math.floor(num/10)
end
"I'm going to use 0 instead of that illegal character code.")
i=0
end
- tex.write(tostring(luatexja.jisx0208.table_jisx0208_uptex[i] or 0))
+ tex.write(tostring(jisx0208.table_jisx0208_uptex[i] or 0))
end
-- \euc: EUC-JP による符号位置 => Unicode 符号位置
end
end
+luatexja.binary_pars.kansujichar = function(c, t)
+ if type(c)~='number' or c<0 or c>9 then
+ ltjb.package_error('luatexja',
+ 'Invalid KANSUJI number (' .. tostring(c) .. ')',
+ 'A KANSUJI number should be in the range 0..9.\n'..
+ 'So I changed this one to zero.')
+ c=0
+ end
+ return ltjs.get_stack_table(stack_table_index.KSJ + c, 0, t)
+end
+
+
local t = {
from_euc = from_euc,
from_kuten = from_kuten,